A simple example to demonstrate the use a looping constraints to solve mathematical expressions-

**The Solution-**

int x; double sum,term; sum=0; for(x=1 ;x<=25 ;x+=3){ term= 1/x; sum=sum+term; } Serial.println("The result is" + sum);

Note that this code can also be written in the form of a while or a do-while loop.

## Comments

## Post a Comment